二十五岁时我们都一样愚蠢、多愁善感,喜欢故弄玄虚,可如果不那样的话,五十岁时也就不会如此明智。
标题:SQL FULL OUTER JOIN 关键字
SQL
FULL OUTER JOIN
关键字只要左表 ( table1 )和右表 ( table2 ) 其中一个表中存在匹配,则返回行也就是说,FULL OUTER JOIN 关键字结合了 LEFT JOIN 和 RIGHT JOIN 的结果
注意 : MySQL 不支持 FULL OUTER JOIN
如果还不理解,那么就看图解
假设我们有两张表 A 和 B
可以看到每个表的最后一条记录是不匹配的,那么
FULL OUTER JOIN
的结果就是SQL FULL OUTER JOIN 语法
SELECT column_name(s) FROM table1 FULL OUTER JOIN table2 ON table1.column_name = table2.column_name ;演示数据
先在 MySQL 数据库运行下面的语句创建测试数据
CREATE DATABASE IF NOT EXISTS twle default character set utf8mb4 collate utf8mb4_unicode_ci; USE twle; DROP TABLE IF EXISTS `lession`; DROP TABLE IF EXISTS `lession_views`; CREATE TABLE `lession` ( id int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT, name varchar(32) default '', views int(11) NOT NULL default '0', created_at DATETIME ); CREATE TABLE `lession_views` ( uniq bigint(20) primary key NOT NULL default '0' , lession_name varchar(32) default '', lession_id int(11) default '0', date_at int(11) NOT NULL default '0', views int(11) NOT NULL default '0' ); INSERT INTO lession(id,name,views,created_at) VALUES (1, 'Python 基础教程',981,'2017-04-18 13:52:03'), (3, 'Ruby 基础教程',199,'2017-05-01 06:16:14'), (4, 'SQL 基础教程', 300,'2017-05-02 08:13:16'); INSERT INTO lession_views(uniq,lession_name,lession_id,date_at,views) VALUES (20170511000001,'Python 基础教程',1,20170511,320), (20170511000002,'Scala 基础教程', 2,20170511,22), (20170511000003,'Ruby 基础教程', 3, 20170511,49), (20170512000001,'Python 基础教程',1,20170512,220), (20170512000002,'Scala 基础教程',2,20170512,12), (20170512000003,'Ruby 基础教程',3,20170512,63), (20170513000001,'Python 基础教程',1,20170513,441), (20170513000002,'Scala 基础教程',2,20170513,39), (20170513000003,'Ruby 基础教程',3,20170513,87);使用
SELECT * FROM lession;
运行结果如下mysql> SELECT * FROM lession; +----+---------------------+-------+---------------------+ | id | name | views | created_at | +----+---------------------+-------+---------------------+ | 1 | Python 基础教程 | 981 | 2017-04-18 13:52:03 | | 3 | Ruby 基础教程 | 199 | 2017-05-01 06:16:14 | | 4 | SQL 基础教程 | 300 | 2017-05-02 08:13:16 | +----+---------------------+-------+---------------------+使用
SELECT * FROM lession_views;
运行结果如下mysql> SELECT * FROM lession_views; +----------------+---------------------+------------+----------+-------+ | uniq | lession_name | lession_id | date_at | views | +----------------+---------------------+------------+----------+-------+ | 20170511000001 | Python 基础教程 | 1 | 20170511 | 320 | | 20170511000002 | Scala 基础教程 | 2 | 20170511 | 22 | | 20170511000003 | Ruby 基础教程 | 3 | 20170511 | 49 | | 20170512000001 | Python 基础教程 | 1 | 20170512 | 220 | | 20170512000002 | Scala 基础教程 | 2 | 20170512 | 12 | | 20170512000003 | Ruby 基础教程 | 3 | 20170512 | 63 | | 20170513000001 | Python 基础教程 | 1 | 20170513 | 441 | | 20170513000002 | Scala 基础教程 | 2 | 20170513 | 39 | | 20170513000003 | Ruby 基础教程 | 3 | 20170513 | 87 | +----------------+---------------------+------------+----------+-------+SQL FULL OUTER JOIN 范例
假设我们要查看所有课程每天的访问量,那么可以使用下面的 SQL 语句
SELECT lession.id,lession.name,lession_views.date_at, lession_views.views FROM lession FULL OUTER JOIN lession_views ON lession.id=lession_views.lession_id ORDER BY lession.id DESC;因为 MySQL 中不支持 FULL OUTER JOIN,但你可以在 SQL Server 测试一下