二十五岁时我们都一样愚蠢、多愁善感,喜欢故弄玄虚,可如果不那样的话,五十岁时也就不会如此明智。
标题:SQL GROUP BY 语句
SQL 中的
GROUP BY
语句根据一个或多个列对结果集进行分组,一般配合聚合函数使用SELECT column_name, aggregate_function(column_name) FROM table_name WHERE column_name operator value GROUP BY column_name;演示数据
先在 MySQL 数据库运行下面的语句创建测试数据
CREATE DATABASE IF NOT EXISTS twle default character set utf8mb4 collate utf8mb4_unicode_ci; USE twle; DROP TABLE IF EXISTS `lession_views`; CREATE TABLE `lession_views` ( uniq bigint(20) primary key NOT NULL default '0' , lession_name varchar(32) NOT NULL default '', lession_id int(11) NOT NULL default '0', date_at int(11) NOT NULL default '0', views int(11) NOT NULL default '0' ); INSERT INTO lession_views(uniq,lession_name,lession_id,date_at,views) VALUES (20170511000001,'Python 基础教程',1,20170511,320), (20170511000002,'Scala 基础教程', 2,20170511,22), (20170511000003,'Ruby 基础教程', 3, 20170511,49), (20170512000001,'Python 基础教程',1,20170512,220), (20170512000002,'Scala 基础教程',2,20170512,12), (20170512000003,'Ruby 基础教程',3,20170512,63), (20170513000001,'Python 基础教程',1,20170513,441), (20170513000002,'Scala 基础教程',2,20170513,39), (20170513000003,'Ruby 基础教程',3,20170513,87);使用
SELECT * FROM lession_views;
运行结果如下+----------------+---------------------+------------+----------+-------+ | uniq | lession_name | lession_id | date_at | views | +----------------+---------------------+------------+----------+-------+ | 20170511000001 | Python 基础教程 | 1 | 20170511 | 320 | | 20170511000002 | Scala 基础教程 | 2 | 20170511 | 22 | | 20170511000003 | Ruby 基础教程 | 3 | 20170511 | 49 | | 20170512000001 | Python 基础教程 | 1 | 20170512 | 220 | | 20170512000002 | Scala 基础教程 | 2 | 20170512 | 12 | | 20170512000003 | Ruby 基础教程 | 3 | 20170512 | 63 | | 20170513000001 | Python 基础教程 | 1 | 20170513 | 441 | | 20170513000002 | Scala 基础教程 | 2 | 20170513 | 39 | | 20170513000003 | Ruby 基础教程 | 3 | 20170513 | 87 | +----------------+---------------------+------------+----------+-------+范例
统计各个课程的总访问量
SELECT lession_name, SUM(views) FROM lession_views GROUP BY lession_name;运行结果输出如下
mysql> SELECT lession_name, SUM(views) FROM lession_views GROUP BY lession_name; +---------------------+------------+ | lession_name | SUM(views) | +---------------------+------------+ | Python 基础教程 | 981 | | Ruby 基础教程 | 199 | | Scala 基础教程 | 73 | +---------------------+------------+SQL GROUP BY 多表连接
GROUP BY
也可以用在多表连接上我们先运行下面的语句创建一张
lession
表DROP TABLE `lession`; CREATE TABLE `lession` ( id int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT, name varchar(32) default '', views int(11) NOT NULL default '0', created_at DATETIME ); INSERT INTO lession(id,name,views,created_at) VALUES (1, 'Python 基础教程',981,'2017-04-18 13:52:03'), (2, 'Scala 基础教程',73,'2017-04-18 16:03:32'), (3, 'Ruby 基础教程',199,'2017-05-01 06:16:14');使用
SELECT * FROM lession;
运行结果如下+----+---------------------+-------+--------------------+ | id | name | views | created_at | +----+---------------------+-------+--------------------+ | 1 | Python 基础教程 | 981 | 2017-04-18 13:52:03 | | 2 | Scala 基础教程 | 73 | 2017-04-18 16:03:32 | | 3 | Ruby 基础教程 | 199 | 2017-05-01 06:16:14 | +----+---------------------+-------+--------------------+总共有 3 条记录
然后我们就可以使用下面的 SQL 语句查看每门课的 总访问量
SELECT lession.name,SUM(lession_views.views) FROM lession,lession_views WHERE lession.id=lession_views.lession_id GROUP BY lession.name;运行结果如下
mysql> SELECT lession.name,SUM(lession_views.views) FROM lession,lession_views WHERE lession.id=lession_views.lession_id GROUP BY lession.name; +---------------------+--------------------------+ | name | SUM(lession_views.views) | +---------------------+--------------------------+ | Python 基础教程 | 981 | | Ruby 基础教程 | 199 | | Scala 基础教程 | 73 | +---------------------+--------------------------+